url-parse.py
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# GNU Mailutils -- a suite of utilities for electronic mail
# Copyright (C) 2009-2012, 2014-2017 Free Software Foundation, Inc.
#
# GNU Mailutils is free software; you can redistribute it and/or modify
# it under the terms of the GNU General Public License as published by
# the Free Software Foundation; either version 3, or (at your option)
# any later version.
#
# GNU Mailutils is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU General Public License for more details.
#
# You should have received a copy of the GNU General Public License
# along with GNU Mailutils. If not, see <http://www.gnu.org/licenses/>.
import sys
from mailutils import url
from mailutils.error import *
def parse (str):
try:
u = url.Url (str)
print "URL: %s" % u
print "\tscheme <%s>" % u.get_scheme ()
print "\tuser <%s>" % u.get_user ()
sec = u.get_secret ()
print "\tpasswd <%s>" % sec.password ()
sec.password_unref ()
print "\tauth <%s>" % u.get_auth ()
print "\thost <%s>" % u.get_host ()
print "\tport %d" % u.get_port ()
print "\tpath <%s>" % u.get_path ()
for i, param in enumerate (u.get_query ()):
print "\tquery[%d] %s" % (i, param)
except UrlError, e:
print e
def parseinput ():
try:
while True:
line = sys.stdin.readline ().strip ()
if line == '':
break
parse (line)
except KeyboardInterrupt:
sys.exit ()
if __name__ == '__main__':
if len (sys.argv) == 1:
parseinput ()
sys.exit ()
for arg in sys.argv[1:]:
if arg == '-':
parseinput ()
else:
parse (arg)